【C++】標準C++を用いてxml中の情報を簡単に解析する

複雑なxml解析器に依存する必要のない解析xmlのラベルを簡単に実現した.
1、例えば以下のxml形式のデータ:

"1.0" encoding="utf-8"?>

  
    MG-APP will be updated automatically
</description>
  </descriptions>
  
  "20200529" path=    "1"/>
  "20200529" path="2"/>
  "20200529" path = "3"/>
  "20200529" path="MG_APP.exe"/>
  "20200529" path="images\splash_logo.jpg"/>
  </files>
</update>

2、解析C++コード:

#include
#include 
#include 
#include 
using namespace std;

//  Parse one item,such as "ver"
void paraseLabel(const char *ch, const char *label, char *var)
{
	char buff[1024] = { 0 };
	strcpy_s(buff, ch);
	// find ver
	char *pStart = NULL, *pEnd = NULL;
	pStart = strstr(buff, label);
	// find first =
	pStart = strstr(pStart, "=");
	// find first "
	pStart = strstr(pStart, "\"");
	pStart += 1;
	// find second "
	pEnd = strstr(pStart, "\"");
	*pEnd = '\0';
	// copy ver
	strcpy_s(var, strlen(pStart) + 1, pStart);
}

int main()
{
	// read file
	ifstream getfile;
	char buff[1024] = { 0 };
	char *p = NULL;
	getfile.open("D:/qupdater.xml");
	while (!getfile.eof())
	{
		getfile.getline(buff, 1024);
		cout << buff << endl;
		p = strstr(buff, ");//  find "
		if (p) {
			char version[512] = { 0 }, filepath[512] = { 0 };
			paraseLabel(buff, "ver", version);
			paraseLabel(buff, "path", filepath);
			cout << version << "->" << filepath << endl;
		}
	}
	getfile.close();
	return 0;
}