NYoj 103大数加算

簡単な問題ですが、以前c++で書いたことがありますが、今日はJavaを見て、Javaで書いてみました.
I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.
A,B must be positive.
入力
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.
しゅつりょく
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation.
サンプル入力

2
1 2
112233445566778899 998877665544332211

サンプル出力

Case 1:
1 + 2 = 3
Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

acコード:

 
import java.util.*;
import java.math.BigInteger;
public class Main {

	/**
	 * @param args
	 */
	
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		
		BigInteger d,dd;
	    int kk,i;
		Scanner cin=new Scanner(System.in);
		kk=cin.nextInt();    	
		for(i=1;i<=kk;++i)	
		{
			d=cin.nextBigInteger();
			dd=cin.nextBigInteger();
			System.out.println("Case "+i+":");
			System.out.println(d+" + "+dd+" = "+d.add(dd));
		}
	}

}