geometry > numpy > pentagon (五角形)の座標を得る | Matplotlibでの描画 > v0.1, v0.2
動作環境
GeForce GTX 1070 (8GB)
ASRock Z170M Pro4S [Intel Z170chipset]
Ubuntu 16.04.4 LTS desktop amd64
TensorFlow v1.7.0
cuDNN v5.1 for Linux
CUDA v8.0
Python 3.5.2
IPython 6.0.0 -- An enhanced Interactive Python.
gcc (Ubuntu 5.4.0-6ubuntu1~16.04.4) 5.4.0 20160609
GNU bash, version 4.3.48(1)-release (x86_64-pc-linux-gnu)
scipy v0.19.1
geopandas v0.3.0
MATLAB R2017b (Home Edition)
ADDA v.1.3b6
gnustep-gui-runtime v0.24.0-3.1
PyMieScatt v1.7.0
処理概要
- Pentagonの形状を得る
- Matplotlibで描画する
code v0.1
geometry_starShaped_180414.ipynb
%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt
'''
v0.1 Apr. 14, 2018
- add get_pentagon()
+ to obtain pentagon geometry
'''
NUM_VERT = 5 # number of vertices (5: for pentagon)
def get_pentagon(radius):
xs, ys = [], []
for idx in range(NUM_VERT):
theta = 2.0 * np.pi * idx / NUM_VERT
theta += np.pi / 2.0 # to put the one vertex upward
xs += [np.cos(theta)]
ys += [np.sin(theta)]
return xs, ys
RAD_INNER = 5
RAD_OUTER = 10
xs, ys = get_pentagon(RAD_INNER)
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax.scatter(xs, ys)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.grid(True)
code v0.2
- Pentagonを上向き、下向きにする引数を追加
- fix bug: get_pentagon() did not use [radius] arg
geometry_starShaped_180414.ipynb
%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt
'''
v0.2 Apr. 14, 2018
- fix bug: get_pentagon() did not use [radius] arg
- get_pentagon() takes [upward] arg
v0.1 Apr. 14, 2018
- add get_pentagon()
+ to obtain pentagon geometry
'''
NUM_VERT = 5 # number of vertices (5: for pentagon)
def get_pentagon(radius, upward):
xs, ys = [], []
for idx in range(NUM_VERT):
theta = 2.0 * np.pi * idx / NUM_VERT
if upward:
theta += np.pi / 2.0 # to put the one vertex upward
else:
theta -= np.pi / 2.0 # to put the one vertex downward
xs += [radius * np.cos(theta)]
ys += [radius * np.sin(theta)]
return xs, ys
RAD_INNER = 5
RAD_OUTER = 10
xs, ys = get_pentagon(RAD_INNER, upward=False)
fig = plt.figure()
ax = fig.add_subplot(1, 1, 1)
ax.scatter(xs, ys)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.grid(True)
Author And Source
この問題について(geometry > numpy > pentagon (五角形)の座標を得る | Matplotlibでの描画 > v0.1, v0.2), 我々は、より多くの情報をここで見つけました https://qiita.com/7of9/items/fa0e7fb3f6b0c87f70cf著者帰属:元の著者の情報は、元のURLに含まれています。著作権は原作者に属する。
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