2022 KAKAO BLIND RECRUITMENT報告結果(lv 1)
10476 ワード
正しいコード
def solution(id_list, report, k):
answer = []
report_dict = {id : [] for id in id_list}
mail_count = {id : 0 for id in id_list}
for r in set(report): #set은 중복 제거용
report_dict[r.split()[1]].append(r.split()[0])
#신고 당한 사람의 딕셔너리에 누가 신고했는지 추가
for key, value in report_dict.items():
if len(value) >= k: #신고 당한 횟수가 k 이상이면
for v in value:
mail_count[v] += 1 # v는 신고자
for i in mail_count:
answer.append(mail_count[i])
return answer
その他の正しいコード
def solution(id_list, report, k):
answer = [0] * len(id_list)
reports = {x : 0 for x in id_list}
for r in set(report):
reports[r.split()[1]] += 1
for r in set(report):
if reports[r.split()[1]] >= k:
answer[id_list.index(r.split()[0])] += 1
return answer
#--------------------------------------------------------
def solution(id_list, report, k):
answer = []
a = list(set(report))
dictionary2 = {name : 0 for name in id_list}
dictionary = {name : [] for name in id_list}
for i in a:
dictionary[i.split()[1]].append(i.split()[0])
for i in dictionary:
if len(dictionary[i]) >= k:
for j in dictionary[i]:
dictionary2[j] += 1
for i in dictionary2:
answer.append(dictionary2[i])
return answer
Reference
この問題について(2022 KAKAO BLIND RECRUITMENT報告結果(lv 1)), 我々は、より多くの情報をここで見つけました https://velog.io/@yibangwon/2022-KAKAO-BLIND-RECRUITMENT-신고-결과-받기テキストは自由に共有またはコピーできます。ただし、このドキュメントのURLは参考URLとして残しておいてください。
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