プログラマー|2018 KAKAO[第一]珂泰JS

フルプールコード 👈🏻 クリックしてGithubに移動

❓ Question 1

📝 My Solution 1

function solution(n, arr1, arr2) {
    const newArr = [];
        for (let i = 0; i<n; i++) {
            let length = 0
            let mix = (arr1[i] | arr2[i])
            let data = ''

while (length < n) {
                data = mix%2 + data
                mix = parseInt(mix/2)
                length++
            }

            let changeNum = data.replace(/1/g,'#').replace(/0/g,' ')
            newArr.push(changeNum)
        }
    return newArr;
}

結果

❓ Question 2

📝 My Solution 2

function solution(dartResult) {
    let bonus = dartResult.split(/[0-9,*#]/).filter(el => el!=='');
    let score = dartResult.split(/[A-Z,*#]/).filter(el => el!=='');
    let option = dartResult.split(/[0-9]/).filter(el=>el!='').join()
    		.split(/[A-Z]/).join('').split(',');
    const newArr = [];

for (let i = 0; i<score.length; i++) {
            if (bonus[i] === 'S') {
                newArr.push(Number(score[i]))
            } else if (bonus[i] === 'D') {
                newArr.push(Number(score[i]) ** 2)
            } else {
                newArr.push(Number(score[i]) ** 3)
            }
        }

for (let i = 0; i<newArr.length; i++) {
            if (option[i] === '*') {
                newArr[i] = newArr[i] * 2;
                newArr[i-1] = newArr[i-1] * 2;
            } else if (option[i] === '#') {
                newArr[i] = newArr[i] * -1
            } else {
                newArr[i] = newArr[i]
            }
        }
    return answer=newArr.reduce((a,b) => a+b)
}

結果