Pythonを利用してある年のある日を計算するのは何曜日ですか

#          

#    ：w=y+[y/4]+[c/4]-2c+[26(m+1）/10]+d-1
import  math
dict = {1: "   ", 2: "   ", 3: "   ", 4: "   ", 5: "   ", 6: "   ", 0: "   "}
while 1:
    y=int(input("     "))
    m=int(input("     "))
    d=int(input("    "))
    if m==1 :
      m=13
      y=y-1
    elif m==2:
      m=14
      y=y-1
    allday=math.floor((y-1)+(y-1)/4-(y-1)/100+(y-1)/400+13*(m+1)/5+(m-1)*28-7+d)
    x=allday%7
    print(dict.get(x,"     "))