ゼロから始まるLCブラシ問題(23):Maximum Depth of Binary Treeツリー深さ
原題:
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree
return its depth = 3.
二叉木の深さを求めてdfsだけでよくて、各ノードは左右のサブツリーの最大値を求めてそして最大値+1を返して、結果:
Success
Runtime: 8 ms, faster than 98.23% of C++ online submissions for Maximum Depth of Binary Tree.
Memory Usage: 19.1 MB, less than 93.50% of C++ online submissions for Maximum Depth of Binary Tree.
コード:
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree
[3,9,20,null,null,15,7]
, 3
/ \
9 20
/ \
15 7
return its depth = 3.
二叉木の深さを求めてdfsだけでよくて、各ノードは左右のサブツリーの最大値を求めてそして最大値+1を返して、結果:
Success
Runtime: 8 ms, faster than 98.23% of C++ online submissions for Maximum Depth of Binary Tree.
Memory Usage: 19.1 MB, less than 93.50% of C++ online submissions for Maximum Depth of Binary Tree.
コード:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int maxDepth(TreeNode* root) {
if (root==NULL){return 0;}
int l=maxDepth(root->left);
int r=maxDepth(root->right);
if (l>=r){return l+1;}
else return r+1;
}
};