python自然対数の底数eを求める
522 ワード
#-*- coding: UTF-8 -*-
'''
Created on 2011-3-3
@author: lihex
e
'''
#
def factorial(number):
if number==1:
return 1
return number*factorial(number-1)
# e^x , x=1 ,n
def sum_toE(n):
retv=2.0
for x in range(2,n+1):
retv += 1/float(factorial(x))
return retv
if __name__ == '__main__':
retv = sum_toE(6)
print retv
転載先:https://www.cnblogs.com/lihex/archive/2011/03/03/1970226.html