杭電acm 1159 Common Subsequence(文字列処理+dp)
2199 ワード
Common Subsequence
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 3 Accepted Submission(s) : 1
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Problem Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = another sequence Z = is a subsequence of X if there exists a strictly increasing sequence of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = is a subsequence of X = with index sequence <1, 2, 4, 6>. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y. The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
Sample Output
Source
Southeastern Europe 2003
考え方:簡単な問題
詳細に注意
コード:
#include
#include
char s[1100];
char s1[1100];
int dir[1100][1100];
int max(int a,int b)
{
return a>b?a:b;
}
int main()
{
while(scanf("%s %s",s,s1)!=EOF)
{
memset(dir,0,sizeof(dir));
int len=strlen(s);
int len1=strlen(s1);
int i,j;
for(i=1;i<=len;i++)
{
for(j=1;j<=len1;j++)
{
if(s[i-1]==s1[j-1])
dir[i][j]=dir[i-1][j-1]+1;
else
dir[i][j]=max(dir[i-1][j],dir[i][j-1]);
}
}
printf("%d",dir[len][len1]);
}
return 0;
}
Time Limit : 2000/1000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 3 Accepted Submission(s) : 1
Font: Times New Roman | Verdana | Georgia
Font Size: ← →
Problem Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = another sequence Z = is a subsequence of X if there exists a strictly increasing sequence of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = is a subsequence of X = with index sequence <1, 2, 4, 6>. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y. The program input is from a text file. Each data set in the file contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct. For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
abcfbc abfcab
programming contest
abcd mnp
Sample Output
4
2
0
Source
Southeastern Europe 2003
考え方:簡単な問題
詳細に注意
コード:
#include
#include
char s[1100];
char s1[1100];
int dir[1100][1100];
int max(int a,int b)
{
return a>b?a:b;
}
int main()
{
while(scanf("%s %s",s,s1)!=EOF)
{
memset(dir,0,sizeof(dir));
int len=strlen(s);
int len1=strlen(s1);
int i,j;
for(i=1;i<=len;i++)
{
for(j=1;j<=len1;j++)
{
if(s[i-1]==s1[j-1])
dir[i][j]=dir[i-1][j-1]+1;
else
dir[i][j]=max(dir[i-1][j],dir[i][j-1]);
}
}
printf("%d",dir[len][len1]);
}
return 0;
}