HDu 2101 A+B Problem Too(数論)

A + B Problem Too
Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8373    Accepted Submission(s): 6277
Problem Description
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
 
Input
Each line will contain two integers A and B. Process to end of file.
 
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
 
Sample Input

   
   
   
   

    
    
    
    1 1
8600 8600
   
   
   
   

 
Sample Output

   
   
   
   

    
    
    
    no
yes
   
   
   
   

 
Source
HDU 2007-6 Programming Contest
 
Recommend
xhd
 
考え方:(10*a+b)%c=((a%c)*10+b)%c;
 

#include<iostream>
using namespace std;
const int mm=100010;
char s[mm],ss[mm];
int main()
{ int ans,anss;
  while(cin>>s>>ss)
  {
    ans=anss=0;
    for(int i=0;s[i]!='\0';i++)
    {
      ans=(ans*10+s[i]-'0')%86;
    }
    for(int i=0;ss[i]!='\0';i++)
      anss=(anss*10+ss[i]-'0')%86;
    ans=(ans+anss)%86;
    if(ans)cout<<"no
";
    else cout<<"yes
";
  }
}