hdoj 1170 Balloon Comes!(水)
2851 ワード
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25161 Accepted Submission(s): 9511
Problem Description
The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem.
Give you an operator (+,-,*,/--denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.
Is it very easy?
Come on, guy! PLMM will send you a beautiful Balloon right now!
Good Luck!
Input
Input contains multiple test cases. The first line of the input is a single integer T (0
Output
For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.
Sample Input
4
+ 1 2
- 1 2
* 1 2
/ 1 2
Sample Output
3
-1
2
0.50
：
#include<stdio.h>
int main()
{
int t,a,b;
char c;
scanf("%d",&t);
while(t--)
{
getchar();//
scanf("%c %d %d",&c,&a,&b);
// scanf("%c%d%d",&c,&a,&b);
if(c=='+')
printf("%d
",a+b);
else if(c=='-')
printf("%d
",a-b);
else if(c=='*')
printf("%d
",a*b);
else
{
if(a%b==0)
printf("%d
",a/b);
else
printf("%.2f
",(float)a/b);// ，
}
}
return 0;
}