jquery ajaxSubmit非同期提出の簡単な実現

フロントjs

$("#nickForm").ajaxSubmit({
     type: "post",
     url: "http://localhost:8080/test/myspace.do?method=updateNick&param=1",
     dataType: "json",
     success: function(result){
           //             
           alert(result.nickMsg);
     }
 });

バックグラウンドパッケージ：

public ActionForward toUpdateNickName(ActionMapping mapping, ActionForm form,
   HttpServletRequest request, HttpServletResponse response){
       PrintWriter pw = response.getWriter();
      JSONObject obj = new JSONObject();
      obj.put("nickMsg", "      ！");
      pw.print(obj);
      pw.close();
}