05-ツリー8 File Transfer(25分)
2805 ワード
05-ツリー8 File Transfer(25分)
We have a network of computters and a list of bi-directional connections.Each of these connections allows a file transfer from one computer to another.Is it possible to send a file from any computter on the network?
Input Specification:
Each input file contains one test case.For each test case,the first line contains N(2≦N≦10 4),the total number of computers in network.Each computer in the network is then represented by the the initine.the infove line.The.The.the infont infont intwent.The.
Output Specification:
For each
Sample Input 1:
考えをかきたてる簡単にセットを調べて、配列でコンピューターの番号を保存しますが、桁が違っています.たとえば、配列0は1号機を貯蓄しています.この位置がずれていることに注意してください.
We have a network of computters and a list of bi-directional connections.Each of these connections allows a file transfer from one computer to another.Is it possible to send a file from any computter on the network?
Input Specification:
Each input file contains one test case.For each test case,the first line contains N(2≦N≦10 4),the total number of computers in network.Each computer in the network is then represented by the the initine.the infove line.The.The.the infont infont intwent.The.
I c1 c2
where I
stands for inputting a connection betwen c1
and c2
;orC c1 c2
where C
stands for checking if it is possible to transfiles between c1
and c2
;orS
where S
stands for stopping this case.Output Specification:
For each
C
case,print in one line the word“yes”or“no”if it is possible or impossible to transfer files between c1
and c2
,respively.At the end of each case,print ine one line「The nectweres.」or「The re are k
components.」where k
is the number of connected components in this network.Sample Input 1:
5
C 3 2
I 3 2
C 1 5
I 4 5
I 2 4
C 3 5
S
Sample Output 1:no
no
yes
There are 2 components.
Sample Input 2:5
C 3 2
I 3 2
C 1 5
I 4 5
I 2 4
C 3 5
I 1 3
C 1 5
S
Sample Output 2:no
no
yes
yes
The network is connected.
考えをかきたてる簡単にセットを調べて、配列でコンピューターの番号を保存しますが、桁が違っています.たとえば、配列0は1号機を貯蓄しています.この位置がずれていることに注意してください.
#include
#include
using namespace std;
int N;
int Find(int* S,int X)
{
if(S[X]<0) return X;
else return S[X]=Find(S,S[X]);// , , */
}
void Union(int* S,int X1,int X2)
{
int root1=Find(S,X1-1);
int root2=Find(S,X2-1);
if(root1==root2)
{
S[root2]=root1;
root1-=root2;
}
else
{
//
if(root1>x1>>x2;
Union(S,x1,x2);
}
void Check_connection(int* S)
{
int x1,x2;
cin>>x1>>x2;
int root1,root2;
root1=Find(S,x1-1);
root2=Find(S,x2-1);
if(root1==root2)
cout<>N;
int S[N];
for(int i=0;i>c;
switch(c)
{
case 'C': Check_connection(S);break;
case 'S': Check_network(S,N);break;
case 'I': Input_connection(S);break;
}
}while(c!='S');
return 0;
}