【二分】HDU 2141 Can You find it?


KIDxの解題はテーマのリンクを報告します:http://acm.hdu.edu.cn/showproblem.php?pid=2141題意はとても簡単でとても良い1本の2分+降維の思想の題です!

#include <iostream>
#include <algorithm>
using namespace std;
#define eps 1e-8
#define PI 3.14159265
#define POW2(x) x*x
#define POW3(x) x*x*x
#define POW4(x) x*x*x*x

int a[505], b[505], c[505], bc[250005];

int main()
{
	int L, N, M, i, j, S, x, cc = 1, l, r, mid, k;
	while (~scanf ("%d%d%d", &L, &N, &M))
	{
		k = 0;
		for (i = 0; i < L; i++)
			scanf ("%d", a+i);
		for (i = 0; i < N; i++)
			scanf ("%d", b+i);
		for (i = 0; i < M; i++)
			scanf ("%d", c+i);
		for (i = 0; i < N; i++)
			for (j = 0; j < M; j++)
				bc[k++] = b[i] + c[j];
		sort (bc, bc+k);
		scanf ("%d", &S);
		printf ("Case %d:
", cc++); while (S--) { scanf ("%d", &x); for (i = 0; i < L; i++) { int tp = x - a[i]; l = 0, r = k - 1; while (l < r) { mid = (l+r) / 2; if (bc[mid] == tp) { puts ("YES"); goto end; } else if (bc[mid] > tp) r = mid; else l = mid + 1; } } puts ("NO"); end:; } } return 0; }