[Leetcode]937. Reorder Data in Log Files
📄 Description
You are given an array of
logs . Each log is a space-delimited string of words, where the first word is the identifier.There are two types of logs:
Reorder these logs so that:
The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
The digit-logs maintain their relative ordering.
Return the final order of the logs.
Example 1:
Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
Explanation:
The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".Example 2:
Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]Constraints:
1 <= logs.length <= 100 3 <= logs[i].length <= 100 logs[i] are separated by a single space. logs[i] is guaranteed to have an identifier and at least one word after the identifier. 💻 My Submission
class Solution:
def reorderLogFiles(self, logs: List[str]) -> List[str]:
digits=[]
letters=[]
for log in logs:
if log.split()[1].isdigit():
digits.append(log)
else:
letters.append(log)
# sort letter-logs
letters.sort(key=lambda x: (x.split()[1:], x.split()[0]))
return letters+digits💡 What I learned
isdigit()関数
数値の有無を判別する関数です.
Referecnes
Reference
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