[BOJ]1660号:区間と5(Java)を求めます

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11660号：区間と5を求めます

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やすり たんい に加える
[ ][ ][ ][ ][ ]
[][o][o]->o部分和:sum(2,5)-sum(2,2)
[][o][o]->o部分和:sum(3,5)-sum(3,2)
oの最終部分と:(sum(2,5)−sum(2,2)+(sum(3,5)−sum(3,2))

コード#コード#

package implement;

import java.util.*;
import java.io.*;

public class Main_11660_구간합구하기5 {
    public static void main(String[] args) throws Exception{
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(br.readLine());
        int N = Integer.parseInt(st.nextToken());
        int M = Integer.parseInt(st.nextToken());
        int[][] map = new int[N][N];
        int[][] sum = new int[N][N]; // 0,0부터 i,j까지 합 저장
        for(int i =0 ; i < N ; i++){
            st = new StringTokenizer(br.readLine());
            for(int j =0 ; j < N ; j++){
                map[i][j] = Integer.parseInt(st.nextToken());
                if(i == 0 && j == 0){
                    sum[i][j] = map[i][j];
                }
                else if(j == 0){
                    sum[i][j] = sum[i-1][N-1]+map[i][j];
                } else{
                    sum[i][j] = sum[i][j-1] + map[i][j];
                }
            }
        }

        StringBuilder sb = new StringBuilder();
        for(int i = 0 ; i < M ; i++){
            st = new StringTokenizer(br.readLine());
            int x1 = Integer.parseInt(st.nextToken())-1;
            int y1 = Integer.parseInt(st.nextToken())-1;
            int x2 = Integer.parseInt(st.nextToken())-1;
            int y2 = Integer.parseInt(st.nextToken())-1;

            /**
             * 줄 단위로 더해줌
             * [ ][ ][ ][ ][ ]
             * [ ][ ][o][o][ ] -> o 부분 합: sum(2,5) - sum(2,2)
             * [ ][ ][o][o][ ] -> o 부분 합: sum(3,5) - sum(3,2)
             *  => o의 최종 부분 합: ( sum(2,5) - sum(2,2) ) + ( sum(3,5) - sum(3,2) )
             */
            int partial = 0;
            for(int j = x1 ; j <= x2 ; j++){
                if(y1 == 0 && j == 0) partial += sum[j][y2];
                else if(y1 == 0) partial += (sum[j][y2] - sum[j-1][N-1]);   
                else partial += (sum[j][y2]-sum[j][y1-1]);
            }
            sb.append(partial+"\n");
        }
        System.out.println(sb.toString());
    }
}