LeetCode Find Minimum In Rotated Sorted Array II
1943 ワード
class Solution {
public:
int findMin(vector<int> &num) {
int L = 0, R = num.size() - 1;
while (L < R && num[L] >= num[R]) {
int mid= (L+R)/2;
if (num[mid] > num[R]) {
L = mid + 1;
} else if (num[mid] < num[R]){
R = mid;
} else {
L++;
}
}
return num[L];
}
};
Follow up for "Find Minimum in Rotated Sorted Array":What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e.,
0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
). Find the minimum element.
The array may contain duplicates.