LeetCode: Reverse Words in a String
6069 ワード
まずextra spaceが必要なものを一つください.
もっといいのをもう一つ
1 class Solution {
2 public:
3 void reverseWords(string &s) {
4 vector<string> S;
5 int pre = 0;
6 string tmp = "";
7 for (int i = 0; i < s.size(); ++i) {
8 if (isspace(s[i]) && tmp.size()) {
9 S.push_back(tmp);
10 tmp.clear();
11 }
12 else if (!isspace(s[i])) tmp += s[i];
13 }
14 if (tmp.size()) S.push_back(tmp);
15 s.clear();
16 for (int i = S.size()-1; i >= 0; --i) {
17 if (i == S.size() - 1) s += S[i];
18 else s = s + " " + S[i];
19 }
20 }
21 };もっといいのをもう一つ
1 class Solution {
2 public:
3 void reverseWords(string &s) {
4 string rs;
5 for (int i = s.size()-1; i >= 0; ) {
6 while (i >= 0 && isspace(s[i])) i--;
7 if (i < 0) break;
8 if (rs.size()) rs += " ";
9 string t;
10 while(i >= 0 && !isspace(s[i])) t += s[i--];
11 int left = 0;
12 int right = t.size()-1;
13 while (left < right) swap(t[left++], t[right--]);
14 rs += t;
15 }
16 s = rs;
17 }
18 };