HDu 5351 MZL's Border(大数)
5386 ワード
タイトルリンク:hdu 5351 MZL's Border
#include <cstdio>
#include <cstring>
#include <queue>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
typedef long long ll;
const int maxn = 1005;
struct bign {
int len, num[300];
bign () {
len = 0;
memset(num, 0, sizeof(num));
}
bign (int number) {*this = number;}
bign (const char* number) {*this = number;}
void DelZero ();
void Put ();
void operator = (int number);
void operator = (char* number);
bool operator < (const bign& b) const;
bool operator > (const bign& b) const { return b < *this; }
bool operator <= (const bign& b) const { return !(b < *this); }
bool operator >= (const bign& b) const { return !(*this < b); }
bool operator != (const bign& b) const { return b < *this || *this < b;}
bool operator == (const bign& b) const { return !(b != *this); }
void operator ++ ();
void operator -- ();
bign operator + (const int& b);
bign operator + (const bign& b);
bign operator - (const int& b);
bign operator - (const bign& b);
bign operator * (const int& b);
bign operator * (const bign& b);
bign operator / (const int& b);
//bign operator / (const bign& b);
int operator % (const int& b);
}F[maxn], M;
const int mod = 258280327;
int N;
char S[maxn];
void init () {
F[0] = 0;
F[1] = 1;
F[2] = 1;
for (int i = 3; i <= 1000; i++)
F[i] = F[i-1] + F[i-2];
}
int solve () {
int n = 0;
while (F[n] <= M + 1) {
n++;
}
return n;
}
int main () {
int cas;
scanf("%d", &cas);
init();
while (cas--) {
scanf("%d%s", &N, S);
M = S;
int k = solve();
/*
F[k-2].Put();
printf("+
");
bign tmp = M - F[k-2];
tmp.Put();
printf("+
");
M.Put();
printf("=
");
*/
int ans = (M - F[k-2]) % mod;
printf("%d
", ans);
}
return 0;
}
void bign::DelZero () {
while (len && num[len-1] == 0)
len--;
if (len == 0) {
num[len++] = 0;
}
}
void bign::Put () {
for (int i = len-1; i >= 0; i--)
printf("%d", num[i]);
}
void bign::operator = (char* number) {
len = strlen (number);
for (int i = 0; i < len; i++)
num[i] = number[len-i-1] - '0';
DelZero ();
}
void bign::operator = (int number) {
len = 0;
while (number) {
num[len++] = number%10;
number /= 10;
}
DelZero ();
}
bool bign::operator < (const bign& b) const {
if (len != b.len)
return len < b.len;
for (int i = len-1; i >= 0; i--)
if (num[i] != b.num[i])
return num[i] < b.num[i];
return false;
}
void bign::operator ++ () {
int s = 1;
for (int i = 0; i < len; i++) {
s = s + num[i];
num[i] = s % 10;
s /= 10;
if (!s) break;
}
while (s) {
num[len++] = s%10;
s /= 10;
}
}
void bign::operator -- () {
if (num[0] == 0 && len == 1) return;
int s = -1;
for (int i = 0; i < len; i++) {
s = s + num[i];
num[i] = (s + 10) % 10;
if (s >= 0) break;
}
DelZero ();
}
bign bign::operator + (const int& b) {
bign a = b;
return *this + a;
}
bign bign::operator + (const bign& b) {
int bignSum = 0;
bign ans;
for (int i = 0; i < len || i < b.len; i++) {
if (i < len) bignSum += num[i];
if (i < b.len) bignSum += b.num[i];
ans.num[ans.len++] = bignSum % 10;
bignSum /= 10;
}
while (bignSum) {
ans.num[ans.len++] = bignSum % 10;
bignSum /= 10;
}
return ans;
}
bign bign::operator - (const int& b) {
bign a = b;
return *this - a;
}
bign bign::operator - (const bign& b) {
int bignSub = 0;
bign ans;
for (int i = 0; i < len || i < b.len; i++) {
bignSub += num[i];
bignSub -= b.num[i];
ans.num[ans.len++] = (bignSub + 10) % 10;
if (bignSub < 0) bignSub = -1;
else bignSub = 0;
}
ans.DelZero ();
return ans;
}
bign bign::operator * (const int& b) {
int bignSum = 0;
bign ans;
ans.len = len;
for (int i = 0; i < len; i++) {
bignSum += num[i] * b;
ans.num[i] = bignSum % 10;
bignSum /= 10;
}
while (bignSum) {
ans.num[ans.len++] = bignSum % 10;
bignSum /= 10;
}
return ans;
}
bign bign::operator * (const bign& b) {
bign ans;
ans.len = 0;
for (int i = 0; i < len; i++){
int bignSum = 0;
for (int j = 0; j < b.len; j++){
bignSum += num[i] * b.num[j] + ans.num[i+j];
ans.num[i+j] = bignSum % 10;
bignSum /= 10;
}
ans.len = i + b.len;
while (bignSum){
ans.num[ans.len++] = bignSum % 10;
bignSum /= 10;
}
}
return ans;
}
bign bign::operator / (const int& b) {
bign ans;
int s = 0;
for (int i = len-1; i >= 0; i--) {
s = s * 10 + num[i];
ans.num[i] = s/b;
s %= b;
}
ans.len = len;
ans.DelZero ();
return ans;
}
int bign::operator % (const int& b) {
bign ans;
long long s = 0;
for (int i = len-1; i >= 0; i--) {
s = s * 10 + num[i];
ans.num[i] = s/b;
s %= b;
}
return s;
}