Leetcode 157,158, Read N Characters Given Read4

    public int read(char[] buf, int n) {
        char[] buffer = new char[4];
        int total = 0;
    	
        boolean eof = false; //end of file
        while(!eof && total < n){
            int count = read4(buffer);
            if(count < 4){
                eof = true;
            }
            // get the actual count
            count = Math.min(count, n - total);
            for(int i = 0; i< count; i++){
                buf[total++] = buffer[i];
            }
        }
        return total;
    }

参照先:http://www.cnblogs.com/anne-vista/p/4865612.html

    private int offSet = 0;
    private int remaining = 0;
    
    private boolean eof = false;
    private char[] buffer = new char[4];
    /**
     * @param buf Destination buffer
     * @param n   Maximum number of characters to read
     * @return    The number of characters read
     */
    public int read(char[] buf, int n) {
        int total = 0;
        while (total < n && (remaining != 0 || !eof)) {
            int count = 0;
            if (remaining != 0) {
            	count = remaining;
            } else {
                offSet = 0;
                count = read4(buffer);
                if (count != 4) {
                	eof = true;
                }
            }
            int length = Math.min(n - total, count);
            for (int i= offSet; i

参照:https://leetcode.com/discuss/19581/clean-accepted-java-solution