ロケット方程式の圧制

コード2019日1の出現

タスク：Xのどこに解決する.

X = the sum of the fuel requirements

例入力

12
14
1969
100756

第1部

私の作業アルゴリズムの記述

Split the input at each newline character to generate an array of strings
Coerce each string to a number
For each number, accumulate a number - starting at 0
  Add to the accumulating number the sum of that number and the current number divided by 3, rounded down, and decremented by 2
Return the accumulated number

私の作業アルゴリズムの視覚的描写

第2部

私の作業アルゴリズムの記述

Sub-routine: Recursive Fuel
- Accept a number as input
If the number is less than or equal to 0
  Return 0
Else
  Return the sum of the input number and the number returned from calling this sub-routine with the number resulting from dividing the input number by 3, rounding down, and decrementing by 2

Split the input at each newline character to generate an array of strings
Coerce each string to a number
For each number, accumulate a number - starting at 0
  Add to the accumulating number the number returned from calling Recursive Fuel with the number resulting from dividing the current number by 3, rounding down, and decrementing by 2
Return the accumulated number

私の作業アルゴリズムの視覚的描写