[Letcode 15]税金の合計
21547 ワード
# 배열을 입력받아 합으로 0을 만들 수 있는 3개의 엘리먼트를 출력
# nums = [-1,0,1,2,-1,-4]
# nums = [-4,-1,-1,0,1,2]
def threeSum(nums):
result = []
left, right = 0, len(nums)-1
flipped = 0
nums.sort()
while not left == right:
twoSum = nums[left] + nums[right]
if -twoSum in nums[left + 1 : right] and \
[nums[left],-twoSum,nums[right]] not in result:
result.append([nums[left],-twoSum,nums[right]])
if flipped == 0:
left += 1
flipped = 1
else:
right -= 1
flipped = 0
return result
if __name__ =="__main__":
nums = [-1,0,1,2,-1,-4]
print(threeSum(nums))
# output
#
# [
# [-1,0,1],
# [-1,-1,2]
# ]
IndexError: list index out of rangetwoSum = nums[left] + nums[right]
Line 9 in threeSum (Solution.py)
def threeSum_brute_force(nums):
result = []
nums.sort()
for i in range(len(nums)-2):
if i>0 and nums[i] == nums[i-1]:
continue
for j in range(i+1, len(nums)-1):
if j > i+1 and nums[j] == nums[j-1]:
continue
for k in range(j+1, len(nums)):
if k > j+1 and nums[k] == nums[k-1]:
continue
if nums[i] + nums[j] + nums[k] == 0:
result.append((nums[i], nums[j], nums[k]))
return result
タイムアウトダブルポインタマージ計算
# 배열을 입력받아 합으로 0을 만들 수 있는 3개의 엘리먼트를 출력
# nums = [-2, 0, 1, 1, 2]
# nums.sort
# nums = [-2,0,1,1,2]
def threeSum_two_pointer(nums):
results = []
nums.sort()
for i in range(len(nums)-2):
if i > 0 and nums[i] == nums[i-1]:
continue
left,right = i+1, len(nums) -1
while left < right:
sum = nums[i] + nums[left] + nums[right]
if sum < 0:
left += 1
elif sum > 0:
right -= 1
else:
# sum == 0
results.append((nums[i],nums[left],nums[right]))
while left < right and nums[left] == nums[left+1]:
left += 1
while left < right and nums[right] == nums[right-1]:
right -= 1
left += 1
right -= 1
return results
def threeSum_brute_force(nums):
result = []
nums.sort()
for i in range(len(nums)-2):
if i>0 and nums[i] == nums[i-1]:
continue
for j in range(i+1, len(nums)-1):
if j > i+1 and nums[j] == nums[j-1]:
continue
for k in range(j+1, len(nums)):
if k > j+1 and nums[k] == nums[k-1]:
continue
if nums[i] + nums[j] + nums[k] == 0:
result.append((nums[i], nums[j], nums[k]))
return result
if __name__ =="__main__":
nums = [-2,0,1,1,2]
print(threeSum_two_pointer(nums))
# output
#
# [
# [-1,0,1],
# [-1,-1,2]
# ]
Reference
この問題について([Letcode 15]税金の合計), 我々は、より多くの情報をここで見つけました https://velog.io/@ithingv/세수의-합テキストは自由に共有またはコピーできます。ただし、このドキュメントのURLは参考URLとして残しておいてください。
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