python文法学習練習1

Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.1310 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.

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IDLE 1.2.1      
>>> ================================ RESTART ================================
>>> s ='abc'
>>> for a in s:
	print a
	;
	
SyntaxError: invalid syntax
>>> print s
abc
>>> for a in a:print a


Traceback (most recent call last):
  File "<pyshell#6>", line 1, in <module>
    for a in a:print a
NameError: name 'a' is not defined
>>> for a in s:print a

a
b
c
>>> str='akakak'
>>> str=str.replace('k',' 8')
>>> print str
a 8a 8a 8
>>> str='akakak'str=str.replace('k',' 8')str='akakak'
SyntaxError: invalid syntax
>>> str='akakak'
>>> str=str.replace('k','8')
>>> print str
a8a8a8
>>> str='a,hello'
>>> print str.find('hello')
2
>>> str='a,b,c,d'
>>> strlist=str.split(',')
>>> for value in strlist: print value

a
b
c
d
>>> def getclass(txt_s):
	str_array=txt_s.split('#')
	return str_array[0]

>>> print getclass('chen3#4.6men')
chen3
>>> print getclass('       ?# ?
     38.42 ?)
	       
SyntaxError: EOL while scanning single-quoted string
>>> print getclass('       ?# ?)
       ?
>>> t=getclass('       ?# ?)
>>> print t
       ?
>>> for a in t:print a

?
?
?
?
?
?
?
?
?
?
1
>>> num=-1
>>> print num
-1
>>> for a in t:
	if(a>=0 && a<=9):
		
SyntaxError: invalid syntax
>>> for a in t:
	if(a>=0 and a<=9):
		print a

		
>>> for a int t:
	
SyntaxError: invalid syntax
>>> for a in t:
	if(a==1) print a
	
SyntaxError: invalid syntax
>>> for a in t:
	if(a=='1'): print a

	
1
>>> dkbh=''
>>> for a in t:
	if(a=='1'):
		if(dkbh==''):
			dkbh=a
		else
		
SyntaxError: invalid syntax
>>> i=1
>>> while i<10:
	i+=1
	if i%2>0:
		continue
	print i

	
2
4
6
8
10
>>> print i
10
>>> i=1
>>> while 1:
	print i
	i+=1
	if(i>10):
		break

	
1
2
3
4
5
6
7
8
9
10
>>> def getclass(txt_s):
dkbh=''
for a in t:
	if(a=='1' or a=='2' or a=='3' or a=='4'):
		if(dkbh==''):
			dkbh=a
        else:		
            dkbh+=a
return dkbh
  File "<pyshell#68>", line 2
    dkbh=''
       ^
IndentationError: expected an indented block
>>> str='a,b,c,d'
>>> strlist=str.split(',')
>>> for value in strlist:
	print value

	
a
b
c
d
>>> def myadd(a=1,b=100):
	result=0
	i=a
	while i<=b:
		result+=i
		i+=1
	return result

>>> print myadd(1,10)
55
>>> print myadd()
5050
>>> print myadd(50)
3825
>>>  def getclass(txt_s):
dkbh=''
for a in txt_s:
	if(a=='1' or a=='2' or a=='3' or a=='4'):
		if(dkbh==''):
			dkbh=a
        else:		
            dkbh+=a
return dkbh
  File "<pyshell#85>", line 1
    def getclass(txt_s):
   ^
IndentationError: unexpected indent
>>> ================================ RESTART ================================
>>> a=1
>>> a.isnumeric()

Traceback (most recent call last):
  File "<pyshell#87>", line 1, in <module>
    a.isnumeric()
AttributeError: 'int' object has no attribute 'isnumeric'
>>> a.isnumeric

Traceback (most recent call last):
  File "<pyshell#88>", line 1, in <module>
    a.isnumeric
AttributeError: 'int' object has no attribute 'isnumeric'
>>> txt_s='sfsfsd3#2.6'
>>> print txt_s
sfsfsd3#2.6
>>> t=txt_s[0:txt_s.find('#')]
>>> print t
sfsfsd3
>>> print t.isdigit()
False
>>> for a in t: print a.isdigit()

False
False
False
False
False
False
True
>>> print t
sfsfsd3
>>> dkbh=''
>>> for a in t:
	if(a.isdigit()==true):
		if(dkbh==''):
			dkbh=a
		else
		
SyntaxError: invalid syntax
>>> for a in t:
	if(a.isdigit()==true):
		if(dkbh==''):
			dkbh=a
		else:
			dkbh+=a

    

Traceback (most recent call last):
  File "<pyshell#105>", line 2, in <module>
    if(a.isdigit()==true):
NameError: name 'true' is not defined
>>> for a in t:
	if(a.isdigit()==True):
		if(dkbh==''):
			dkbh=a
		else:
			dkbh+=a

			
>>> print dkbh
3
>>>