LeetCode 129 Swap Nodes in Pairs
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
分析:
これはReverse Node in k-Groupsの考え方と同じですが、ここのkは2になりました.
For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
分析:
これはReverse Node in k-Groupsの考え方と同じですが、ここのkは2になりました.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode swapPairs(ListNode head) {
if(head==null || head.next==null)
return head;
ListNode dummy = new ListNode(0);
dummy.next = head;
ListNode pre = dummy;
while(pre.next != null && pre.next.next != null){
ListNode first = pre.next;
ListNode second = pre.next.next;
//
first.next = second.next;
second.next = first;
pre.next = second;
//
pre = first;
}
return dummy.next;
}
}