JSONのSuperObject(6):方法
3015 ワード
SuperObjectのJSONオブジェクトに「方法」が含まれているのは興味深い.メソッドのフォーマットは次のとおりです.
テストコード:
procedure Method(const This, Params: ISuperObject; var Result: ISuperObject);
// , :
TSuperType = (stNull, stBoolean, stDouble, stInt, stObject, stArray, stString, stMethod);
テストコード:
unit Unit1;
interface
uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls, Keyboard;
type
TForm1 = class(TForm)
Button1: TButton;
Button2: TButton;
procedure Button1Click(Sender: TObject);
procedure Button2Click(Sender: TObject);
end;
var
Form1: TForm1;
implementation
{$R *.dfm}
uses SuperObject;
// 1; ,
procedure Method1(const This, Params: ISuperObject; var Result: ISuperObject);
begin
ShowMessage('Hello');
end;
// 2; ;
procedure Method2(const This, Params: ISuperObject; var Result: ISuperObject);
begin
ShowMessage(Params.AsJSon);
end;
// 3; ; ,
procedure Method3(const This, Params: ISuperObject; var Result: ISuperObject);
begin
ShowMessage(This.AsJSon);
end;
// 4; ; , ,
procedure Method4(const This, Params: ISuperObject; var Result: ISuperObject);
begin
Result := This;
Result.Merge(Params, True); { }
end;
//
procedure TForm1.Button1Click(Sender: TObject);
var
jo: ISuperObject;
begin
jo := SO('{"X":"Y"}');
jo.M['jm1'] := @Method1;
jo.M['jm2'] := @Method2;
jo.M['jm3'] := @Method3;
jo.M['jm4'] := @Method4;
jo.call('jm1'); // Hello
jo.call('jm2', SO('{"A":"B"}')); // {"A":"B"}
jo.call('jm2', '{"A":"B"}'); // {"A":"B"}
jo.call('jm3'); // {"X":"Y"}
jo.call('jm4', '{"B":null}');
ShowMessage(jo.AsJSon); // {"X":"Y","B":null}
end;
//
procedure TForm1.Button2Click(Sender: TObject);
var
t,jo: ISuperObject;
begin
jo := SO('{"X":"Y"}');
jo.M['jm1'] := @Method1;
jo.M['jm2'] := @Method2;
jo.M['jm3'] := @Method3;
jo.M['jm4'] := @Method4;
jo['jm1()']; // Hello
jo['jm2(' + '{"A":"B"}' + ')']; // {"A":"B"}
jo['jm2({A:B})']; // {"A":"B"}
jo['jm3()']; // {"X":"Y"}
jo['jm4(' + '{"B":null}' + ')'];
ShowMessage(jo.AsJSon); // {"X":"Y","B":null}
end;
end.