sql serverデータフィールド(テーブルのフィールドとタイプ情報)の取得
4280 ワード
データフィールドの取得(テーブルのフィールドとタイプ情報)
転載先:https://www.cnblogs.com/newlangwen/p/9438739.html
SELECT
=case when a.colorder=1 then d.name else '' end,
=case when a.colorder=1 then isnull(f.value,'') else '' end,
=a.colorder,
=a.name,
=case when COLUMNPROPERTY(a.id,a.name,'IsIdentity')=1 then '√'else '' end,
=case when exists(SELECT 1 FROM sysobjects where xtype='PK' and name in (
SELECT name FROM sysindexes WHERE indid in(
SELECT indid FROM sysindexkeys WHERE id = a.id AND colid=a.colid
))) then '√' else '' end,
=b.name,
=a.length,
=COLUMNPROPERTY(a.id,a.name,'PRECISION'),
=isnull(COLUMNPROPERTY(a.id,a.name,'Scale'),0),
=case when a.isnullable=1 then '√'else '' end,
=isnull(e.text,''),
=isnull(g.[value],'')
FROM syscolumns a
left join systypes b on a.xtype=b.xusertype
inner join sysobjects d on a.id=d.id and d.xtype='U' and d.name<>'dtproperties'
left join syscomments e on a.cdefault=e.id
left join sys.extended_properties g on a.id=g.major_id and a.colid=g.minor_id
left join sys.extended_properties f on d.id=f.major_id and f.minor_id =0
--where d.name=' ' -- ,
order by a.id,a.colorder
転載先:https://www.cnblogs.com/newlangwen/p/9438739.html