最も簡単なC++呼び出しLua

#pragma comment(lib, "lua5.1.lib") 


extern "C" {
#include "lua.h"
#include "lualib.h"
#include "lauxlib.h"
}


#include <iostream>
#include <string>
using namespace std;

lua_State* L;

void init()
{
/*    Lua */  
L = lua_open();  
// L = luaL_newstate(); 
luaL_openlibs(L);  /*   Lua    */  
}

void close()
{
/*   Lua */  
lua_close(L);  
}


//////////////////////////////////////////////////////////
//1.C++  lua  
void test_script()
{
luaL_dofile(L, "Lua1.lua");	 /*      */    
}
//////////////////////////////////////////////////////////
//2. C++  Lua       
int cppCallLua(int x,int y)
{
int sum;
lua_getglobal(L,"add");	//   
lua_pushnumber(L,x);
lua_pushnumber(L,y);
lua_call(L,2,1);
sum = (int)lua_tonumber(L,-1);
lua_pop(L,1);
return sum;
}


void test_function()
{
int sum;
luaL_dofile(L, "luaadd.lua");  
sum = cppCallLua(10,15);
printf("after lua_add The sum is %d
", sum);
}

print("Loading lua add successful..")
function add(x,y)
 return x + y
end


add(1,2)