HDU 6197 array array array(2017瀋陽テニス-最長上昇サブシーケンス)
タイトル:
n個の数を教えて、k個の数を除いたかどうかを聞いた後、元のシーケンスは非厳格な増加シーケンスまたは非厳格な減少シーケンスになります.
考え方:
明らかに1回のLISを求めて、逆さまにして一方のLISを求めて、ansとkの関係を比較すればいいです.
array array array
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 219 Accepted Submission(s): 131
Problem Description
One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan blocked Kiddo's path to escape from the museum. But Kiddo didn't want to give it back. So, Kiddo asked Conan a question. If Conan could give a right answer, Kiddo would return the ring to the museum.
Kiddo: "I have an array
A and a number
k, if you can choose exactly
k elements from
A and erase them, then the remaining array is in non-increasing order or non-decreasing order, we say
A is a magic array. Now I want you to tell me whether
A is a magic array. "Conan: "emmmmm..."Now, Conan seems to be in trouble, can you help him?
Input
The first line contains an integer T indicating the total number of test cases. Each test case starts with two integers
n and
k in one line, then one line with
n integers:
A1,A2…An.
1≤T≤20
1≤n≤105
0≤k≤n
1≤Ai≤105
Output
For each test case, please output "A is a magic array."if it is a magic array. Otherwise, output "A is not a magic array."(without quotes).
Sample Input
3 4 1 1 4 3 7 5 2 4 1 3 1 2 6 1 1 4 3 5 4 6
Sample Output
A is a magic array. A is a magic array. A is not a magic array.
Source
2017 ACM/ICPC Asia Regional Shenyang Online
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n個の数を教えて、k個の数を除いたかどうかを聞いた後、元のシーケンスは非厳格な増加シーケンスまたは非厳格な減少シーケンスになります.
考え方:
明らかに1回のLISを求めて、逆さまにして一方のLISを求めて、ansとkの関係を比較すればいいです.
#include
#include
#include
using namespace std;
int T;
const int maxn = 100000 + 10;
int a[maxn], c[maxn];
int main(){
scanf("%d",&T);
while(T--){
int n, k;
scanf("%d %d",&n, &k);
for (int i = 0; i < n; ++i){
scanf("%d", a+i);
}
int cnt = 0;
int ans = 0;
for (int i = 0; i < n; ++i){
int p = upper_bound(c, c + cnt, a[i]) - c;
if (p == cnt){
c[cnt++] = a[i];
ans = max(ans, cnt);
}
else {
c[p] = a[i];
}
}
cnt = 0;
for (int i = n-1; i >= 0; --i){
int p = upper_bound(c, c + cnt, a[i]) - c;
if (p == cnt){
c[cnt++] = a[i];
ans = max(ans, cnt);
}
else {
c[p] = a[i];
}
}
// printf("ans = %d
", ans);
if (n - k <= ans){
puts("A is a magic array.");
}
else {
puts("A is not a magic array.");
}
}
return 0;
}
array array array
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 219 Accepted Submission(s): 131
Problem Description
One day, Kaitou Kiddo had stolen a priceless diamond ring. But detective Conan blocked Kiddo's path to escape from the museum. But Kiddo didn't want to give it back. So, Kiddo asked Conan a question. If Conan could give a right answer, Kiddo would return the ring to the museum.
Kiddo: "I have an array
A and a number
k, if you can choose exactly
k elements from
A and erase them, then the remaining array is in non-increasing order or non-decreasing order, we say
A is a magic array. Now I want you to tell me whether
A is a magic array. "Conan: "emmmmm..."Now, Conan seems to be in trouble, can you help him?
Input
The first line contains an integer T indicating the total number of test cases. Each test case starts with two integers
n and
k in one line, then one line with
n integers:
A1,A2…An.
1≤T≤20
1≤n≤105
0≤k≤n
1≤Ai≤105
Output
For each test case, please output "A is a magic array."if it is a magic array. Otherwise, output "A is not a magic array."(without quotes).
Sample Input
3 4 1 1 4 3 7 5 2 4 1 3 1 2 6 1 1 4 3 5 4 6
Sample Output
A is a magic array. A is a magic array. A is not a magic array.
Source
2017 ACM/ICPC Asia Regional Shenyang Online
Recommend
liuyiding | We have carefully selected several similar problems for you: 6205 6204 6203 6202 6201