PHPでLINQ

<?php
    // Ginq
    require_once('path/to/ginq/Ginq.php');

    $sample1 = ['John', 'Peter', 'Joe', 'Patrick', 'Donald', 'Eric', 'Joe'];

    // SELECT name FROM sample1 WHERE LENGTH(name) < 5
    $under5 = Ginq::from($sample1)
        ->where(function($name){return strlen($name) < 5;})
        ->toArray();

    // SELECT DISTINCT name FROM sample1 ORDER BY id DESC
    $reverse = Ginq::from($sample1)->reverse()->distinct()->toArray();

    // Employee PHPLinqのサンプルのコピペ
    class Employee {
        public $Id, $DepartmentId, $ManagerId, $Name, $Email, $Age;
        public function __construct($id = 0, $departmentId = 0, $managerId = 0, $name = '', $email = '', $age = '') {
            $this->Id               = $id;
            $this->DepartmentId     = $departmentId;
            $this->ManagerId        = $managerId;
            $this->Name             = $name;
            $this->Email            = $email;
            $this->Age              = $age;
        }
    }
    $employees = [
        new Employee(1, 1, 5, 'Maarten', '[email protected]', 24),
        new Employee(2, 1, 5, 'Paul', '[email protected]', 30),
        new Employee(3, 2, 5, 'Bill', '[email protected]', 29),
        new Employee(4, 3, 5, 'Bill', '[email protected]', 28),
        new Employee(5, 2, 0, 'Xavier', '[email protected]', 40)
    ];

    // SELECT Email, SUBSTR(Email, INSTR(Email,'@')+1) FROM employees WHERE LENGTH(Name) = 4 ORDER BY Age DESC LIMIT 2 OFFSET 1
    $result = Ginq::from($employees)
        ->where(function($employee){ return strlen($employee->Name) === 4; })
        ->orderByDesc(function($employee){ return $employee->Age; })
        ->drop(1)->take(2)
        ->select(function($employee){ return [
            'EmailAddress' => $employee->Email,
            'Domain' => substr($employee->Email, strpos($employee->Email, "@") + 1)
            ]; })
        ->toArray();