C経典二分検索法
1.keyに基づいて配列の位置を検索する
2.数を挿入し、その配列の位置を得る
#include <stdio.h>
/* key = 9; 1 2 3 4 5 6 7 8 arr 3, 4, 5, 7, 9 , 11, 21, 23 low = 1 mid = (low + high)/2 = 4 high = 8; one arr[mid] = 7 < 9; so low = mid + 1 = 5; high = 8; mid = (low + high)/2 = 6 two arr[mid] = 11 > 9 so low = 5 , high = mid - 1 = 5 mid = 5; arr[mid] = 9 == key if(key = 10) low = mid + 1 > high */
int main(int argc, const char * argv[])
{
int findByHalf(int arr[], int len, int key);
int arr[] = {3, 4 , 5, 7, 9 , 11, 21, 23};
int len = sizeof(arr)/sizeof(int);
int index = findByHalf(arr, len, 88);
printf("index = %d
", index);
return 0;
}
int findByHalf(int arr[], int len, int key){
int low = 0;
int high = len - 1;
int mid ;
while(low <= high){
mid = (low + high) / 2;
//
if (key > arr[mid]) {
low = mid + 1;
//
}else if (key > arr[mid]) {
high = mid - 1;
}else{
return mid;
}
}
return -1;
}
2.数を挿入し、その配列の位置を得る
#include <stdio.h>
/* key = 9; 1 2 3 4 5 6 7 8 arr 3, 4, 5, 7, 9 , 11, 21, 23 low = 1 mid = (low + high)/2 = 4 high = 8; one arr[mid] = 7 < 9; so low = mid + 1 = 5; high = 8; mid = (low + high)/2 = 6 two arr[mid] = 11 > 9 so low = 5 , high = mid - 1 = 5 mid = 5; arr[mid] = 9 == key if(key = 10) low = mid + 1 > high */
int main(int argc, const char * argv[])
{
int findByHalf(int arr[], int len, int key);
int arr[] = {3, 4 , 5, 7, 9 , 11, 21, 23};
int len = sizeof(arr)/sizeof(int);
int index = findByHalf(arr, len, 88);
printf("index = %d
", index);
return 0;
}
int insertByHalf(int arr[], int len, int key){
int low = 0;
int high = len - 1;
int mid ;
while(low <= high){
mid = (low + high) / 2;
//
if (key > arr[mid]) {
low = mid + 1;
//
}else if (key > arr[mid]) {
high = mid - 1;
}else{
// arr[mid] == key
// key
return mid + 1;
}
}
// low > high key > arr[mid];
// key low
return low;
}