Condition秩序印刷ABCD
2439 ワード
プログラムを作成し、3つのスレッドを開き、この3つのスレッドのIDはそれぞれA、B、Cであり、各スレッドは自分のIDを画面に10回印刷し、出力結果はABCの順序で表示しなければならない.如:ABCABC....順番に押す.
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
/**
* @author zjq
* @date 2020/3/25 16:56
*
* ADC
*/
public class pcC {
public static void main(String[] args) {
Data3 data3 = new Data3();
new Thread(()->{
for(int i=0;i<10;i++){
data3.printA();
}
},"A").start();
new Thread(()->{
for(int i=0;i<10;i++){
data3.printB();
}
},"B").start();
new Thread(()->{
for(int i=0;i<10;i++){
data3.printC();
}
},"C").start();
}
}
class Data3{// Lock
private Lock lock = new ReentrantLock();
Condition condition1 = lock.newCondition();
Condition condition2 = lock.newCondition();
Condition condition3 = lock.newCondition();
private int num = 1;//num=1 A;num = 2 B;num =3 C
public void printA(){
lock.lock();
try {
//
while(num!=1){
condition1.await();
}
System.out.println(Thread.currentThread().getName()+"=======A");
//
num = 2;
condition2.signal();
}catch (Exception e){
e.printStackTrace();
}finally {
lock.unlock();
}
}
public void printB(){
lock.lock();
try {
// ， -》 -》
while(num!=2){
condition2.await();
}
System.out.println(Thread.currentThread().getName()+"=========B");
num = 3;
condition3.signal();
}catch (Exception e){
e.printStackTrace();
}finally {
lock.unlock();
}
}
public void printC(){
lock.lock();
try {
//
while (num!=3){
condition3.await();
}
System.out.println(Thread.currentThread().getName()+"========C");
num = 1;
condition1.signal();
}catch (Exception e){
e.printStackTrace();
}finally {
lock.unlock();
}
}
}