rubyローマ数字とアラビア数字を変換する方法
2075 ワード
def number_to_roma(n)
#
number = [1,4,5,9,10,40,50,90,100,400,500,900,1000]
roma = ["I","IV","V","IX","X","XL","L","XC","C","CD","D","CM","M"]
hash = number.zip(roma).inject({}) {|r,ele| r[ele.first] = ele.last;r}
# 、 、 、 , 2 , 10000
temp = 3.step(0,-1).inject([]) do |r,ele|
r << n/(10**ele)
n %= 10**ele
r
end
# ,
temp.reverse!
#
result = ""
3.step(0,-1).each do |i|
# , "M" *
if i == 3
result << "M"*temp[i]
next
end
#temp[i]*(10**i) , number
# , hash
# , 5
# 5, (100,10,1) (C,X,I) *
# 5, (500,50,5)(D,L,V) + (C,X,I) * -5
if number.include?(temp[i]*(10**i))
result << hash[temp[i]*(10**i)]
else
temp[i].to_i < 5 ? result << hash[10**i]*temp[i] : result << (hash[5*(10**i)]+hash[10**i]*(temp[i]-5))
end
end
#
result
end
p number_to_roma(1661)
p number_to_roma(1990)
p number_to_roma(2008)
def roma_to_number(string)
#
number = [1,4,5,9,10,40,50,90,100,400,500,900,1000]
roma = ["I","IV","V","IX","X","XL","L","XC","C","CD","D","CM","M"]
hash = roma.zip(number).inject({}) {|r,ele| r[ele.first] = ele.last; r}
#
reg = /M|CM|D|CD|C|XC|L|XL|X|IX|V|IV|I/
# scan ,
temp = string.scan(reg)
# , , 。 。
temp.uniq.inject(0) do |r,ele|
r += temp.count(ele)*hash[ele]
end
end
p roma_to_number("MDCLXI")
p roma_to_number("MCMXC")
p roma_to_number("MMVIII")