FJの文字列/*問題記述FJは、A 1=「A」A 2=「ABA」A 3=「ABACABA」A 4=「ABACABADABACABA」…

import java.util.Scanner;
public class ABA {
	public static void main(String[] args) {
		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt();
		arrayMethod(n);
	}
	 public static void arrayMethod(int n){
		 
	    	String[] s1={"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
	    	String[] s2={"A"};
	    	if(n==1)printArray(s2);//    1，    A
	    	else{
	    	for(int i=2;i<=n;i++){
	    		s2=Method(s2,s1[i-1]);
	    	}
	    	printArray(s2);
	    	}
	 }
	  
	public static String[] Method(String[] s,String s2){//       ：     s,   s2
    	String[] str=new String[s.length*2+1];
    	for(int i=0;i

まず数字を入力し、結果を出力します.スケール(1-23)