50 SQL
Student(S#,Sname,Sage,Ssex) S# ，
Course(C#,Cname,T#) C# ，
SC(S#,C#,score)
Teacher(T#,Tname) T# ，
：
1、 “001” “002” ；
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score
from SC where C#='002') b
where a.score>b.score and a.s#=b.s#;
2、 60 ；
select S#,avg(score)
from sc
group by S# having avg(score) >60;
3、 、 、 、 ；
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student left Outer join SC on Student.S#=SC.S#
group by Student.S#,Sname
4、 “ ” ；
select count(distinct(Tname))
from Teacher
where Tname like ' %';
5、 “ ” 、 ；
select Student.S#,Student.Sname
from Student
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=' ');
6、 “001” “002” 、 ；
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002');
7、 “ ” 、 ；
select S#,Sname
from Student
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname=' ' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname=' '));
8、 “002” “001” 、 ；
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 <score;
9、 60 、 ；
select S#,Sname
from Student
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60);
10、 、 ；
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);
11、 “1001” ；
select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
12、 “001” ；
select distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S# and C# in (select C# from SC where S#='001');
13、 “SC” “ ” ；
update SC set score=(select avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname=' ');
14、 “1002” ；
select S# from SC where C# in (select C# from SC where S#='1002')
group by S# having count(*)=(select count(*) from SC where S#='1002');
15、 “ ” SC ；
Delect SC
from course ,Teacher
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname=' ';
16、 SC ， ： “003” 、2、
；
Insert SC select S#,'002',(Select avg(score)
from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002');
17、 “ ”、“ ”、“ ” ， ： ID,, , , , ,
SELECT S# as ID
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS
,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS
,COUNT(*) AS , AVG(t.score) AS
FROM SC AS t
GROUP BY S#
ORDER BY avg(t.score)
18、 ： ： ID， ，
SELECT L.C# As ID,L.score AS ,R.score AS
FROM SC L ,SC AS R
WHERE L.C# = R.C# and
L.score = (SELECT MAX(IL.score)
FROM SC AS IL,Student AS IM
WHERE L.C# = IL.C# and IM.S#=IL.S#
GROUP BY IL.C#)
AND
R.Score = (SELECT MIN(IR.score)
FROM SC AS IR
WHERE R.C# = IR.C#
GROUP BY IR.C#
);
19、
SELECT t.C# AS ,max(course.Cname)AS ,isnull(AVG(score),0) AS
,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS
FROM SC T,Course
where t.C#=course.C#
GROUP BY t.C#
ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC
20、 ( "1 " ): （001）， （002），OO&UML （003）， （004）
SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS
,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS
,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS
,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS
,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML
,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML
,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS
,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS
FROM SC
21、
SELECT max(Z.T#) AS ID,MAX(Z.Tname) AS ,C.C# AS ＩＤ,MAX(C.Cname) AS ,AVG(Score) AS
FROM SC AS T,Course AS C ,Teacher AS Z
where T.C#=C.C# and C.T#=Z.T#
GROUP BY C.C#
ORDER BY AVG(Score) DESC
22、 3 6 ： （001）， （002），UML （003）， （004）
[ ID],[ ], , ,UML, ,
SELECT DISTINCT top 3
SC.S# As ,
Student.Sname AS ,
T1.score AS ,
T2.score AS ,
T3.score AS UML,
T4.score AS ,
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as
FROM Student,SC LEFT JOIN SC AS T1
ON SC.S# = T1.S# AND T1.C# = '001'
LEFT JOIN SC AS T2
ON SC.S# = T2.S# AND T2.C# = '002'
LEFT JOIN SC AS T3
ON SC.S# = T3.S# AND T3.C# = '003'
LEFT JOIN SC AS T4
ON SC.S# = T4.S# AND T4.C# = '004'
WHERE student.S#=SC.S# and
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
NOT IN
(SELECT
DISTINCT
TOP 15 WITH TIES
ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0)
FROM sc
LEFT JOIN sc AS T1
ON sc.S# = T1.S# AND T1.C# = 'k1'
LEFT JOIN sc AS T2
ON sc.S# = T2.S# AND T2.C# = 'k2'
LEFT JOIN sc AS T3
ON sc.S# = T3.S# AND T3.C# = 'k3'
LEFT JOIN sc AS T4
ON sc.S# = T4.S# AND T4.C# = 'k4'
ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);
23、 , : ID, ,[100-85],[85-70],[70-60],[ <60]
SELECT SC.C# as ID, Cname as
,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85]
,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70]
,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60]
,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP BY SC.C#,Cname;
24、
SELECT 1+(SELECT COUNT( distinct )
FROM (SELECT S#,AVG(score) AS
FROM SC
GROUP BY S#
) AS T1
WHERE > T2. ) as ,
S# as ,
FROM (SELECT S#,AVG(score)
FROM SC
GROUP BY S#
) AS T2
ORDER BY desc;
25、 :( )
SELECT t1.S# as ID,t1.C# as ID,Score as
FROM SC t1
WHERE score IN (SELECT TOP 3 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
26、
select c#,count(S#) from sc group by C#;
27、
select SC.S#,Student.Sname,count(C#) AS
from SC ,Student
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1;
28、 、
Select count(Ssex) as from Student group by Ssex having Ssex=' ';
Select count(Ssex) as from Student group by Ssex having Ssex=' '；
29、 “ ”
SELECT Sname FROM Student WHERE Sname like ' %';
30、 ，
select Sname,count(*) from Student group by Sname having count(*)>1;;
31、1981 ( ：Student Sage datetime)
select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age
from student
where CONVERT(char(11),DATEPART(year,Sage))='1981';
32、 ， ， ，
Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ;
33、 85 、
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S# group by SC.S#,Sname having avg(score)>85;
34、 “ ”， 60
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname=' 'and score <60;
35、 ；
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S# and SC.C#=Course.C# ;
36、 70 、 ；
SELECT distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70 AND SC.S#=student.S#;
37、 ，
select c# from sc where scor e <60 order by C# ;
38、 003 80 ；
select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003';
39、
select count(*) from sc;
40、 “ ” ，
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname=' ' and SC.score=(select max(score)from SC where C#=C.C# );
41、
select count(*) from sc group by C#;
42、 、 、
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ;
43、
SELECT t1.S# as ID,t1.C# as ID,Score as
FROM SC t1
WHERE score IN (SELECT TOP 2 score
FROM SC
WHERE t1.C#= C#
ORDER BY score DESC
)
ORDER BY t1.C#;
44、 （ 10 ）。 ， ， ， ，
select C# as ,count(*) as
from sc
group by C#
order by count(*) desc,c#
45、
select S#
from sc
group by s#
having count(*) > = 2
46、
select C#,Cname
from Course
where C# in (select c# from sc group by c#)
47、 “ ”
select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname=' ');
48、
select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#;
49、 “004” 60，
select S# from SC where C#='004'and score <60 order by score desc;
50、 “002” “001”
delete from Sc where S#='001'and C#='001';