【POJ3069】Saruman's Army

8501 ワード

Description Saruman the White must lead his army along a straight path from Isengard to Helm’s Deep. To keep track of his forces, Saruman distributes seeing stones, known as palantirs, among the troops. Each palantir has a maximum effective range of R units, and must be carried by some troop in the army (i.e., palantirs are not allowed to “free float” in mid-air). Help Saruman take control of Middle Earth by determining the minimum number of palantirs needed for Saruman to ensure that each of his minions is within R units of some palantir.
Input The input test file will contain multiple cases. Each test case begins with a single line containing an integer R, the maximum effective range of all palantirs (where 0 ≤ R ≤ 1000), and an integer n, the number of troops in Saruman’s army (where 1 ≤ n ≤ 1000). The next line contains n integers, indicating the positions x1, …, xn of each troop (where 0 ≤ xi ≤ 1000). The end-of-file is marked by a test case with R = n = −1.
Output For each test case, print a single integer indicating the minimum number of palantirs needed.
Sample Input 0 3 10 20 20 10 7 70 30 1 7 15 20 50 -1 -1
Sample Output 2 4
Hint In the first test case, Saruman may place a palantir at positions 10 and 20. Here, note that a single palantir with range 0 can cover both of the troops at position 20. In the second test case, Saruman can place palantirs at position 7 (covering troops at 1, 7, and 15), position 20 (covering positions 20 and 30), position 50, and position 70. Here, note that palantirs must be distributed among troops and are not allowed to “free float.” Thus, Saruman cannot place a palantir at position 60 to cover the troops at positions 50 and 70.
Source Stanford Local 2006
貪欲な問題を初めて探して、知能指数の思惟能力の着手点を考察するのは基本的に最も端に位置する兵士の位置(だから先に序列を並べなければならない)で、いずれにしても最も端の兵士は必ずpalantirの影響範囲R内にあるため、これによって第1のpalantirの位置を確定して更にしばらく考えてから第1のpalantirがちょうど影響しないその兵士の位置を発見して、「一番端の兵士の位置」は同じ性質のものなので、ループを書くことができます
//Matsuri 
#include
#include
#define MAXN 2001
using namespace std;
int n,r,x[MAXN];int ans=0;
void solve()
{
	int i=1; //     ,            ,                 
	sort(x+1,x+n+1);
	while(i<=n)
	{
		int s=x[i]; //s      r           
		//  s       r   ,    s    palantir
		while(i<=n && x[i]<=s+r) i++;
		int p=x[i-1]; //p   palantir      ,       
		while(i<=n && x[i]<=p+r) i++; 
		ans++;
	}	
	printf("%d
"
,ans); } int main() { while(scanf("%d%d",&r,&n)!=EOF) { if (r==-1 || n==-1) break; ans=0; for (int i=1;i<=n;i++) scanf("%d",&x[i]); solve(); } return 0; }