【ブラシ問題】【C++】Valid Number問題

leetcode元アドレス:https://leetcode.com/problems/valid-number/
原題:
Validate if a given string is numeric.
Some examples: "0"  =>  true " 0.1 "  =>  true "abc"  =>  false "1 a"  =>  false "2e10"  =>  true
Note: It is intended for the problem statement to be ambiguous. You should gather all requirements up front before implementing one.
Update (2015-02-10): The signature of the  C++  function had been updated. If you still see your function signature accepts a  const char *  argument, please click the reload button  to reset your code definition.

enNumber(string s){

	//        ，           ，    ，e   ，   ，     
	int count = 0,pointCount = 0,eCount = 0,spaceCount = 0,negCount = 0;
	//        ，               ，            ，e   ，     
	int firstNum,lastNum,eNum = s.length(),pointNum = -1;

	//           
	for (int i = 0; i < s.length() ; i++)
	{
		if (s[i] != ' '){
			firstNum = i;
			break;
		}
		else{
			spaceCount++;
		}
	}

	//                false
	if (spaceCount == s.length())
		return false;

	//        
	for (int i = s.length() - 1; i >= 0; i--){
		if (s[i] != ' '){
			lastNum = i;
			break; 
		}
	}

	//       
	string subString (s, firstNum, lastNum - firstNum + 1);

	//        
	for (int i = 0; i < subString.length(); i++){
		
		//            1
		if (subString[i] >= '0'&&subString[i] <= '9'){
			count++;
		}
		//      ，           
		else if (subString[i] == '.')
		{
			pointNum = i;
			pointCount++;
		}
		//  e   ，        e   
		else if (subString[i] == 'e')
		{
			eCount++;
			if (i1 && subString[i - 1] == 'e'&&(subString.length()-1)>i)
				negCount++;
		}
	}
	//      1 ，       ，       0   e   ，      0-9      
	if (pointCount == 1 && count > 0 && pointNum= '0'))
			{
				count++;
			}
		}
		//      1，         ，      0-9   ，      0-9    e   
		else if ((subString[pointNum - 1] >= '0'&&subString[pointNum - 1] <= '9') || (subString[pointNum + 1] >= '0'&&subString[pointNum + 1] <= '9')||subString[pointNum+1]=='e')
			count++;
	}

	// e    1，       0， e          ， e            
	if (eCount == 1 && count > 0&&eNum > 0&&eNum 0&&subString[eNum-1]!='-'&&subString[eNum-1]!='+')
		count++;

	//      0-2    
	if (negCount >= 0 && negCount <= 2)
		count += negCount;

	//              ，        ，    
	if (count == subString.length())
		return true;
	else
		return false;
}