sqlデータベースに注入して修復する二つの実例的な方法
2140 ワード
1.第一の場合は、指定された注入文字列を全て置換する必要がある（注入文字列のみを空にする）
declare @delStr nvarchar(500)
set @delStr='<script src=https://www.jb51.net/js/common.js></script>' --
/****************************************/
/********** ************/
set nocount on
declare @tableName nvarchar(100),@columnName nvarchar(100),@tbID int,@iRow int,@iResult int
declare @sql nvarchar(2000)
set @iResult=0
declare cur cursor for
select name,id from sysobjects where xtype='U'
open cur
fetch next from cur into @tableName,@tbID
while @@fetch_status=0
begin
declare cur1 cursor for
select name from syscolumns where xtype in (231,167,239,175, 35, 99) and id=@tbID
open cur1
fetch next from cur1 into @columnName
while @@fetch_status=0
begin
set @sql='update [' + @tableName + '] set ['+ @columnName +']= SUBSTRING([' + @columnName + '],' + '1, PATINDEX( ''%' + @delStr + '%'', [' + @columnName + '])-1) + ' + 'SUBSTRING([' + @columnName + '], PATINDEX( ''%' + @delStr + '%'', [' + @columnName + ']) + ' + 'len(''' + @delStr + ''') , datalength([' + @columnName + '])) where ['+@columnName+'] like ''%'+@delStr+'%'''
exec sp_executesql @sql
set @iRow=@@rowcount
set @iResult=@iResult+@iRow
if @iRow>0
begin
print ' ：'+@tableName+', :'+@columnName+' '+convert(varchar(10),@iRow)+' ;'
end
fetch next from cur1 into @columnName
end
close cur1
deallocate cur1
fetch next from cur into @tableName,@tbID
end
print ' '+convert(varchar(10),@iResult)+' !!!'
close cur
deallocate cur
set nocount off